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tAn15度是多少

tan15° =tan(60°-45°) =(tan60°- tan45°)/(1+ tan60°*tan45°) =(根号3 -1)/(1+根号3) =(根号3-1)*(根号3-1)/[(根号3+1)(根号3-1)] =(4-2根号3)/2 =2-根号3 亲,答题不易。记得好评奥~

tan15° =tan(60°-45°) =(tan60°- tan45°)/(1+ tan60°*tan45°) =(√3 -1)/(1+√3) =(√3-1)*(√3-1)/[(√3+1)(√3-1)] =(4-2√3)/2 =2-√3

答: tan15° =tan(60°-45°) =(tan60°- tan45°)/(1+ tan60°*tan45°) =(根号3 -1)/(1+根号3) =(根号3-1)*(根号3-1)/[(根号3+1)(根号3-1)] =(4-2根号3)/2 =2-根号3

tan15° =tan(60°-45°) =(tan60°-tan45°)/(1+tan60°tan45°) =(√3-1)/(1+√3) =(√3-1)²/[(1+√3)(√3-1)] =(4-2√3)/2 =2-√3

求采纳

tan15° =tan(60°-45°) =(tan60°- tan45°)/(1+ tan60°*tan45°) =(根号3 -1)/(1+根号3) =(根号3-1)*(根号3-1)/[(根号3+1)(根号3-1)] =(4-2根号3)/2 =2-根号3

tan15° =tan(60°-45°) =(tan60°- tan45°)/(1+ tan60°*tan45°) =(根号3 -1)/(1+根号3) =(根号3-1)*(根号3-1)/[(根号3+1)(根号3-1)] =(4-2根号3)/2 =2-根号3 tan60°=根号3 tan60°*tan15°=根号3*(2-根号3)=2*根号3-3

1+tan15度除以1-tan15度 =(tan45°+tan15°)/(1-tan45°tan15°) =tan(45°+15°) =tan60° =√3

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